Question presented to candidate: "You are given two lists of integers, each already sorted in ascending order. Write a Python function that returns one sorted list containing every element of both. Then tell me how you would do it if the first list had empty slots at the end and I wanted the merge done in place."
What a strong answer should cover:
- The two-pointer merge: compare the fronts, append the smaller, advance that pointer, then add the leftovers of whichever list is not used up.
- O(m + n) time and O(m + n) output space, compared with O((m + n) log(m + n)) for re-sorting from scratch.
- Using
<=so equal items from the first list come first (a stable merge), and why that matters for records. - The in-place variant (LeetCode 88): fill
nums1from the back so nothing unread is overwritten; O(1) extra space. - Python specifics:
result.extend(a[i:])copies the tail (slicing makes a copy),heapq.mergeexists and returns a lazy generator, andsorted(a + b)is correct but does more work than needed.
Clarifying questions expected:
- "New list, or merge into the first list in place?"
- "Can either list be empty, and can there be duplicates?"
Code / implementation expected: Yes โ a Python merge(a, b) with two indices, and ideally the from-the-back in-place version.